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Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, You should be doing int x = *((int *)arg); You are casting from void * to int that is why you get the warning. If your code has the chance to ever be ported to some platform where this doesn't hold, this won't work. Implicit conversions - cppreference.com To cast such pointers to 32-bit types and vice versa special functions are used: void * Handle64ToHandle ( const void * POINTER_64 h ) void * POINTER_64 HandleToHandle64 ( const void *h ) long HandleToLong ( const void *h ) unsigned long HandleToUlong ( const void *h ) The proper way is to cast it to another pointer type. Fix for objc/45925 Unless you have a valid address at that value, you are going to invoke undefined behaviour when try to use that pointer. Casting int to void* : r/C_Programming - reddit I am compiling this program in linux gcc compiler.. Using printf with a pointer to float gives an error, Meaning of int (*) (int *) = 5 (or any integer value), Casting int to void* loses precision, and what is the solution in required cases, Acidity of alcohols and basicity of amines. In the first example, the variable c1 of the char type is converted to a temporary variable of the int type, because the second operand in the division operation, the constant 2, is of the higher type int. Can Martian regolith be easily melted with microwaves? windows meson: cast to 'HANDLE' (aka 'void *') from smaller integer "because the type "int" supports only -32768 ~ 32768" This is not true for any modern desktop or mobile OS or any OS that is targeted by cocos2d-x. LLNL's tutorial is bad and they should feel bad. Did i have to face to unexpected runtime issues, i guess not, i've found another discussion on this -.