bohr was able to explain the spectra of the

In the nineteenth century, chemists used optical spectroscopes for chemical analysis. Bohrs model of the hydrogen atom gave an exact explanation for its observed emission spectrum. The invention of precise energy levels for the electrons in an electron cloud and the ability of the electrons to gain and lose energy by moving from one energy level to another offered an explanation for how atoms were able to emit exact frequencies . In presence of the magnetic field, each spectral line gets split up into fine lines, the phenomenon is known as Zeeman effect. id="addMyFavs"> The Pfund series of lines in the emission spectrum of hydrogen corresponds to transitions from higher excited states to the n = 5 orbit. What is the frequency of the spectral line produced? First, energy is absorbed by the atom in the form of heat, light, electricity, etc. What is the name of this series of lines? Similarly, the blue and yellow colors of certain street lights are caused, respectively, by mercury and sodium discharges. In what region of the electromagnetic spectrum would the electromagnetic r, The lines in the emission spectrum of hydrogen result from: a. energy given off in the form of a photon of light when an electron "jumps" from a higher energy state to a lower energy state. Bohr model of the atom - IU Related Videos The Balmer series is the series of emission lines corresponding to an electron in a hydrogen atom transitioning from n 3 to the n = 2 state. Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. These transitions are shown schematically in Figure \(\PageIndex{4}\). Also, the higher the n, the more energy an Bohr model - eduTinker Telecommunications systems, such as cell phones, depend on timing signals that are accurate to within a millionth of a second per day, as are the devices that control the US power grid. Imagine it is a holiday, and you are outside at night enjoying a beautiful display of fireworks. Substituting the speed into the centripetal acceleration gives us the quantization of the radius of the electron orbit, {eq}r = 4\pi\epsilon_0\frac{n^2\hbar^2}{mZe^2} \space\space\space\space\space n =1, 2, 3, .